What are the solutions to the equation x^2+4x+17=8-2x ?

The solutions to the equation x^2+4x+17=8-2x are x=-3

Find the zeros of x^2+4x+17=8-2x

The zeros of x^2+4x+17=8-2x are x=-3

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x^{2} + 4 x + 17 = 8 - 2 x

x = - 3

Solution steps

x^{2} + 4 x + 17 = 8 - 2 x

Move

2 x

to the left side

x^{2} + 6 x + 17 = 8

Move

8

to the left side

x^{2} + 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

x = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

x = - 3

The solution to the quadratic equation is:

x = - 3

x, x^{2} - 5 x + 4 = 0

0.75 x^{2} - 1.7 x + 0.5 = 0

14 x^{2} = 3, 5 x = 0

3 x^{2} - 3 x - 8 = 0

5 x^{2} - 2 x + 6 = 0

What are the solutions to the equation x^2+4x+17=8-2x ?
The solutions to the equation x^2+4x+17=8-2x are x=-3
Find the zeros of x^2+4x+17=8-2x
The zeros of x^2+4x+17=8-2x are x=-3