What are the solutions to the equation x^2-5x=3x-4x ?

The solutions to the equation x^2-5x=3x-4x are x=4,x=0

Find the zeros of x^2-5x=3x-4x

The zeros of x^2-5x=3x-4x are x=4,x=0

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x^{2} - 5 x = 3 x - 4 x

x = 4, x = 0

Solution steps

x^{2} - 5 x = 3 x - 4 x

Refine

x^{2} - 5 x = - x

Move

x

to the left side

x^{2} - 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

x_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

x = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 4, x = 0

x^{2} - 2 x + 2 = 1

x, x^{2} y^{3} + 2 y = 6 x - 3

7 x^{2} - 11 x + 5 = 0

q, \frac{5 q ^{2}}{R} = \frac{B}{a}

2 x^{2} + 16 x + 28 = 0

What are the solutions to the equation x^2-5x=3x-4x ?
The solutions to the equation x^2-5x=3x-4x are x=4,x=0
Find the zeros of x^2-5x=3x-4x
The zeros of x^2-5x=3x-4x are x=4,x=0