What are the solutions to the equation 7x^2-11x+5=0 ?

The solutions to the equation 7x^2-11x+5=0 are x= 11/14+i(sqrt(19))/(14),x= 11/14-i(sqrt(19))/(14)

Find the zeros of 7x^2-11x+5=0

The zeros of 7x^2-11x+5=0 are x= 11/14+i(sqrt(19))/(14),x= 11/14-i(sqrt(19))/(14)

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7 x^{2} - 11 x + 5 = 0

x = \frac{11}{14} + i \frac{19}{14}, x = \frac{11}{14} - i \frac{19}{14}

Solution steps

7 x^{2} - 11 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 7 \cdot 5}{2 \cdot 7}

Simplify

(- 11)^{2} - 4 \cdot 7 \cdot 5 : 19 i

x_{1, 2} = \frac{- ( - 11 ) \pm 19 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 19 i}{2 \cdot 7}, x_{2} = \frac{- ( - 11 ) - 19 i}{2 \cdot 7}

x = \frac{- ( - 11 ) + 19 i}{2 \cdot 7} : \frac{11}{14} + i \frac{19}{14}

x = \frac{- ( - 11 ) - 19 i}{2 \cdot 7} : \frac{11}{14} - i \frac{19}{14}

The solutions to the quadratic equation are:

x = \frac{11}{14} + i \frac{19}{14}, x = \frac{11}{14} - i \frac{19}{14}

q, \frac{5 q ^{2}}{R} = \frac{B}{a}

2 x^{2} + 16 x + 28 = 0

x, x^{2} y + x y^{2} - 2 x + 2 y - 2 = 0

3 x^{2} + 8 x = - 4

y^{2} + 36 = 0

What are the solutions to the equation 7x^2-11x+5=0 ?
The solutions to the equation 7x^2-11x+5=0 are x= 11/14+i(sqrt(19))/(14),x= 11/14-i(sqrt(19))/(14)
Find the zeros of 7x^2-11x+5=0
The zeros of 7x^2-11x+5=0 are x= 11/14+i(sqrt(19))/(14),x= 11/14-i(sqrt(19))/(14)