What are the solutions to the equation 3x^2+8x=-4 ?

The solutions to the equation 3x^2+8x=-4 are x=-2/3 ,x=-2

Find the zeros of 3x^2+8x=-4

The zeros of 3x^2+8x=-4 are x=-2/3 ,x=-2

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3 x^{2} + 8 x = - 4

x = - \frac{2}{3}, x = - 2

Solution steps

3 x^{2} + 8 x = - 4

Move

4

to the left side

3 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

8^{2} - 4 \cdot 3 \cdot 4 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 3}, x_{2} = \frac{- 8 - 4}{2 \cdot 3}

x = \frac{- 8 + 4}{2 \cdot 3} : - \frac{2}{3}

x = \frac{- 8 - 4}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = - 2

y^{2} + 36 = 0

2 x^{2} + 7 x + 6 = 0

9 x^{2} - 25 x - 30 = 0

(x - 2) (x + 5) = 9 x + 10

2 x^{2} - 8 x - 17 = 0

What are the solutions to the equation 3x^2+8x=-4 ?
The solutions to the equation 3x^2+8x=-4 are x=-2/3 ,x=-2
Find the zeros of 3x^2+8x=-4
The zeros of 3x^2+8x=-4 are x=-2/3 ,x=-2