What are the solutions to the equation 2(x+1)^2-1=9 ?

The solutions to the equation 2(x+1)^2-1=9 are x=sqrt(5)-1,x=-sqrt(5)-1

Find the zeros of 2(x+1)^2-1=9

The zeros of 2(x+1)^2-1=9 are x=sqrt(5)-1,x=-sqrt(5)-1

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2 (x + 1)^{2} - 1 = 9

x = 5 - 1, x = - 5 - 1

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

2 (x + 1)^{2} - 1 = 9

Move

1

to the right side

2 (x + 1)^{2} = 10

Divide both sides by

2

(x + 1)^{2} = 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 5 : x = 5 - 1

Solve

x + 1 = - 5 : x = - 5 - 1

The solutions to the quadratic equation are:

x = 5 - 1, x = - 5 - 1

3 n - 6 = 18 n^{2}

3^{2} = x^{2} + 1^{2}

x^{2} + 3 x (x - 12) = 0

3 x^{2} - 12 x + 5

2 x^{2} - 3 x - 20 = x^{2} + 34

What are the solutions to the equation 2(x+1)^2-1=9 ?
The solutions to the equation 2(x+1)^2-1=9 are x=sqrt(5)-1,x=-sqrt(5)-1
Find the zeros of 2(x+1)^2-1=9
The zeros of 2(x+1)^2-1=9 are x=sqrt(5)-1,x=-sqrt(5)-1