What are the solutions to the equation x^2+3x(x-12)=0 ?

The solutions to the equation x^2+3x(x-12)=0 are x=9,x=0

Find the zeros of x^2+3x(x-12)=0

The zeros of x^2+3x(x-12)=0 are x=9,x=0

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x^{2} + 3 x (x - 12) = 0

x = 9, x = 0

Solution steps

x^{2} + 3 x (x - 12) = 0

Expand

x^{2} + 3 x (x - 12) : 4 x^{2} - 36 x

4 x^{2} - 36 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 36)^{2} - 4 \cdot 4 \cdot 0 = 36

x_{1, 2} = \frac{- ( - 36 ) \pm 36}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 36}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 36}{2 \cdot 4}

x = \frac{- ( - 36 ) + 36}{2 \cdot 4} : 9

x = \frac{- ( - 36 ) - 36}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = 9, x = 0

3 x^{2} - 12 x + 5

2 x^{2} - 3 x - 20 = x^{2} + 34

2 x^{2} + 2 = 10

3 x^{2} - 4 x = - 4

x^{2} - 20 + 12 = 0

What are the solutions to the equation x^2+3x(x-12)=0 ?
The solutions to the equation x^2+3x(x-12)=0 are x=9,x=0
Find the zeros of x^2+3x(x-12)=0
The zeros of x^2+3x(x-12)=0 are x=9,x=0