What are the solutions to the equation 5x^2-4=0 ?

The solutions to the equation 5x^2-4=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

Find the zeros of 5x^2-4=0

The zeros of 5x^2-4=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

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5 x^{2} - 4 = 0

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.89442 \dots, x = - 0.89442 \dots

Solution steps

5 x^{2} - 4 = 0

Move

4

to the right side

5 x^{2} = 4

Divide both sides by

5

x^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{5}, x = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

6 w^{2} - 5 w - 6

(12 5^{\frac{2}{3}})^{\frac{1}{2}}

6 x^{3} + 12 x^{2} y - x - 2 y

2 x^{2} - 12 x = 0

\frac{3}{10} + \frac{1}{4}

What are the solutions to the equation 5x^2-4=0 ?
The solutions to the equation 5x^2-4=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))
Find the zeros of 5x^2-4=0
The zeros of 5x^2-4=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))