What are the solutions to the equation 0=3x(x-1)-(3x+7) ?

The solutions to the equation 0=3x(x-1)-(3x+7) are x=(3+sqrt(30))/3 ,x=(3-sqrt(30))/3

Find the zeros of 0=3x(x-1)-(3x+7)

The zeros of 0=3x(x-1)-(3x+7) are x=(3+sqrt(30))/3 ,x=(3-sqrt(30))/3

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0 = 3 x (x - 1) - (3 x + 7)

x = \frac{3 + 30}{3}, x = \frac{3 - 30}{3}

Decimal Notation

x = 2.82574 \dots, x = - 0.82574 \dots

Solution steps

0 = 3 x (x - 1) - (3 x + 7)

Expand

3 x (x - 1) - (3 x + 7) : 3 x^{2} - 6 x - 7

0 = 3 x^{2} - 6 x - 7

Switch sides

3 x^{2} - 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 7) = 230

x_{1, 2} = \frac{- ( - 6 ) \pm 2 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 30}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 30}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 30}{2 \cdot 3} : \frac{3 + 30}{3}

x = \frac{- ( - 6 ) - 2 30}{2 \cdot 3} : \frac{3 - 30}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 30}{3}, x = \frac{3 - 30}{3}

10 x^{2} + 5 = 1

25 = x^{2} + 14 x + 49

2 x^{2} - 3 x = - 2

115 + 12.25 t - 4.9 t^{2}

(m - 3) x^{2} + (m - 7) x + 2 = 0

What are the solutions to the equation 0=3x(x-1)-(3x+7) ?
The solutions to the equation 0=3x(x-1)-(3x+7) are x=(3+sqrt(30))/3 ,x=(3-sqrt(30))/3
Find the zeros of 0=3x(x-1)-(3x+7)
The zeros of 0=3x(x-1)-(3x+7) are x=(3+sqrt(30))/3 ,x=(3-sqrt(30))/3