What are the solutions to the equation 0=-x^2+5x-4 ?

The solutions to the equation 0=-x^2+5x-4 are x=1,x=4

Find the zeros of 0=-x^2+5x-4

The zeros of 0=-x^2+5x-4 are x=1,x=4

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0 = - x^{2} + 5 x - 4

x = 1, x = 4

Solution steps

0 = - x^{2} + 5 x - 4

Switch sides

- x^{2} + 5 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

5^{2} - 4 (- 1) (- 4) = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3}{2 ( - 1 )}

x = \frac{- 5 + 3}{2 ( - 1 )} : 1

x = \frac{- 5 - 3}{2 ( - 1 )} : 4

The solutions to the quadratic equation are:

x = 1, x = 4

2 n^{2} + 15 n + 7 = 0

x^{2} + m x + 7 = 0, m > 0

3 x^{2} - x = - 2

2 y^{2} = 6 y

- 7 x - 4 = - 3 x^{2}

What are the solutions to the equation 0=-x^2+5x-4 ?
The solutions to the equation 0=-x^2+5x-4 are x=1,x=4
Find the zeros of 0=-x^2+5x-4
The zeros of 0=-x^2+5x-4 are x=1,x=4