What are the solutions to the equation 3x^2-x=-2 ?

The solutions to the equation 3x^2-x=-2 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6

Find the zeros of 3x^2-x=-2

The zeros of 3x^2-x=-2 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6

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3 x^{2} - x = - 2

x = \frac{1}{6} + i \frac{23}{6}, x = \frac{1}{6} - i \frac{23}{6}

Solution steps

3 x^{2} - x = - 2

Move

2

to the left side

3 x^{2} - x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

Simplify

(- 1)^{2} - 4 \cdot 3 \cdot 2 : 23 i

x_{1, 2} = \frac{- ( - 1 ) \pm 23 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 23 i}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 23 i}{2 \cdot 3}

x = \frac{- ( - 1 ) + 23 i}{2 \cdot 3} : \frac{1}{6} + i \frac{23}{6}

x = \frac{- ( - 1 ) - 23 i}{2 \cdot 3} : \frac{1}{6} - i \frac{23}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} + i \frac{23}{6}, x = \frac{1}{6} - i \frac{23}{6}

2 y^{2} = 6 y

- 7 x - 4 = - 3 x^{2}

s^{2} + s + 4 = 0

3 x^{2} + 10 x - 17 = - 9

x^{2} + 4 x - 72 = 5 x

What are the solutions to the equation 3x^2-x=-2 ?
The solutions to the equation 3x^2-x=-2 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6
Find the zeros of 3x^2-x=-2
The zeros of 3x^2-x=-2 are x= 1/6+i(sqrt(23))/6 ,x= 1/6-i(sqrt(23))/6