What are the solutions to the equation v^2+8v+16=0 ?

The solutions to the equation v^2+8v+16=0 are v=-4

Find the zeros of v^2+8v+16=0

The zeros of v^2+8v+16=0 are v=-4

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v^{2} + 8 v + 16 = 0

v = - 4

Solution steps

v^{2} + 8 v + 16 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

v_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

v = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

v = - 4

The solution to the quadratic equation is:

v = - 4

7 w^{2} = 448

x^{2} - 51 = 14 x

x^{2} + 20 x + 28 = 0

x (4 x + 7) = 2

2 x^{2} + 30 = 16 x

What are the solutions to the equation v^2+8v+16=0 ?
The solutions to the equation v^2+8v+16=0 are v=-4
Find the zeros of v^2+8v+16=0
The zeros of v^2+8v+16=0 are v=-4