What are the solutions to the equation x(4x+7)=2 ?

The solutions to the equation x(4x+7)=2 are x= 1/4 ,x=-2

Find the zeros of x(4x+7)=2

The zeros of x(4x+7)=2 are x= 1/4 ,x=-2

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x (4 x + 7) = 2

x = \frac{1}{4}, x = - 2

Solution steps

x (4 x + 7) = 2

Expand

x (4 x + 7) : 4 x^{2} + 7 x

4 x^{2} + 7 x = 2

Move

2

to the left side

4 x^{2} + 7 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

7^{2} - 4 \cdot 4 (- 2) = 9

x_{1, 2} = \frac{- 7 \pm 9}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 7 + 9}{2 \cdot 4}, x_{2} = \frac{- 7 - 9}{2 \cdot 4}

x = \frac{- 7 + 9}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 7 - 9}{2 \cdot 4} : - 2

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 2

2 x^{2} + 30 = 16 x

4 - x^{2} = 1 - \frac{1}{4} x^{2}

x^{2} = 15 x - 54

9 x^{2} - 10 x = 0

- 5 n^{2} - 3 n - 52 = 2 - 7 n^{2}

What are the solutions to the equation x(4x+7)=2 ?
The solutions to the equation x(4x+7)=2 are x= 1/4 ,x=-2
Find the zeros of x(4x+7)=2
The zeros of x(4x+7)=2 are x= 1/4 ,x=-2