What are the solutions to the equation -5n^2-3n-52=2-7n^2 ?

The solutions to the equation -5n^2-3n-52=2-7n^2 are n=6,n=-9/2

Find the zeros of -5n^2-3n-52=2-7n^2

The zeros of -5n^2-3n-52=2-7n^2 are n=6,n=-9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 n^{2} - 3 n - 52 = 2 - 7 n^{2}

n = 6, n = - \frac{9}{2}

Solution steps

- 5 n^{2} - 3 n - 52 = 2 - 7 n^{2}

Move

7 n^{2}

to the left side

2 n^{2} - 3 n - 52 = 2

Move

2

to the left side

2 n^{2} - 3 n - 54 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 54 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 54) = 21

n_{1, 2} = \frac{- ( - 3 ) \pm 21}{2 \cdot 2}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 21}{2 \cdot 2}, n_{2} = \frac{- ( - 3 ) - 21}{2 \cdot 2}

n = \frac{- ( - 3 ) + 21}{2 \cdot 2} : 6

n = \frac{- ( - 3 ) - 21}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

n = 6, n = - \frac{9}{2}

x^{2} = - 625

- 5 x^{2} + 15 x + 65 = 0

x^{2} = - 20 x

4 x^{2} + 169 = 0

x^{2} + 8 x + 2 = 22

What are the solutions to the equation -5n^2-3n-52=2-7n^2 ?
The solutions to the equation -5n^2-3n-52=2-7n^2 are n=6,n=-9/2
Find the zeros of -5n^2-3n-52=2-7n^2
The zeros of -5n^2-3n-52=2-7n^2 are n=6,n=-9/2