What are the solutions to the equation (3y-2)^2=18 ?

The solutions to the equation (3y-2)^2=18 are y=(3sqrt(2)+2)/3 ,y=(-3sqrt(2)+2)/3

Find the zeros of (3y-2)^2=18

The zeros of (3y-2)^2=18 are y=(3sqrt(2)+2)/3 ,y=(-3sqrt(2)+2)/3

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(3 y - 2)^{2} = 18

y = \frac{3 2 + 2}{3}, y = \frac{- 3 2 + 2}{3}

Solution steps

(3 y - 2)^{2} = 18

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 y - 2 = 18 : y = \frac{3 2 + 2}{3}

Solve

3 y - 2 = - 18 : y = \frac{- 3 2 + 2}{3}

The solutions to the quadratic equation are:

y = \frac{3 2 + 2}{3}, y = \frac{- 3 2 + 2}{3}

(x + 1) (x - 3) = 12

5 x^{2} - 4 x - 1 = 0

4 x (x - 3) = 0

x, x^{2} - 9 y^{2} + 4 x + 4 = 0

x^{2} + x - 2 = 0

What are the solutions to the equation (3y-2)^2=18 ?
The solutions to the equation (3y-2)^2=18 are y=(3sqrt(2)+2)/3 ,y=(-3sqrt(2)+2)/3
Find the zeros of (3y-2)^2=18
The zeros of (3y-2)^2=18 are y=(3sqrt(2)+2)/3 ,y=(-3sqrt(2)+2)/3