What are the solutions to the equation factor 5x^2-4x-1=0 ?

The solutions to the equation factor 5x^2-4x-1=0 are x=-1/5 ,x=1

Find the zeros of factor 5x^2-4x-1=0

The zeros of factor 5x^2-4x-1=0 are x=-1/5 ,x=1

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5 x^{2} - 4 x - 1 = 0

x = - \frac{1}{5}, x = 1

Decimal Notation

x = - 0.2, x = 1

Solution steps

5 x^{2} - 4 x - 1 = 0

Factor

5 x^{2} - 4 x - 1 : (5 x + 1) (x - 1)

(5 x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

5 x + 1 = 0 or x - 1 = 0

Solve

5 x + 1 = 0 : x = - \frac{1}{5}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = 1

4 x (x - 3) = 0

x, x^{2} - 9 y^{2} + 4 x + 4 = 0

x^{2} + x - 2 = 0

98 - 6 x^{2} = 0

5 x^{2} - 4 x - 16 = 0

What are the solutions to the equation factor 5x^2-4x-1=0 ?
The solutions to the equation factor 5x^2-4x-1=0 are x=-1/5 ,x=1
Find the zeros of factor 5x^2-4x-1=0
The zeros of factor 5x^2-4x-1=0 are x=-1/5 ,x=1