What are the solutions to the equation 5x^2-4x-16=0 ?

The solutions to the equation 5x^2-4x-16=0 are x=(2(1+sqrt(21)))/5 ,x=(2(1-sqrt(21)))/5

Find the zeros of 5x^2-4x-16=0

The zeros of 5x^2-4x-16=0 are x=(2(1+sqrt(21)))/5 ,x=(2(1-sqrt(21)))/5

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5 x^{2} - 4 x - 16 = 0

x = \frac{2 ( 1 + 21 )}{5}, x = \frac{2 ( 1 - 21 )}{5}

Solution steps

5 x^{2} - 4 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 16 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 16) = 421

x_{1, 2} = \frac{- ( - 4 ) \pm 4 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 21}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 4 21}{2 \cdot 5}

x = \frac{- ( - 4 ) + 4 21}{2 \cdot 5} : \frac{2 ( 1 + 21 )}{5}

x = \frac{- ( - 4 ) - 4 21}{2 \cdot 5} : \frac{2 ( 1 - 21 )}{5}

The solutions to the quadratic equation are:

x = \frac{2 ( 1 + 21 )}{5}, x = \frac{2 ( 1 - 21 )}{5}

6 x^{2} - 12 x = 0

- 24 (1 - x)^{2} + 4 π x^{2} = 0

x, x^{2} y^{2} + x y = 2

m^{2} + m - 12 = 0

x^{2} + 3 x + 14 = 0

What are the solutions to the equation 5x^2-4x-16=0 ?
The solutions to the equation 5x^2-4x-16=0 are x=(2(1+sqrt(21)))/5 ,x=(2(1-sqrt(21)))/5
Find the zeros of 5x^2-4x-16=0
The zeros of 5x^2-4x-16=0 are x=(2(1+sqrt(21)))/5 ,x=(2(1-sqrt(21)))/5