What are the solutions to the equation x^2+3x+14=0 ?

The solutions to the equation x^2+3x+14=0 are x=-3/2+i(sqrt(47))/2 ,x=-3/2-i(sqrt(47))/2

Find the zeros of x^2+3x+14=0

The zeros of x^2+3x+14=0 are x=-3/2+i(sqrt(47))/2 ,x=-3/2-i(sqrt(47))/2

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x^{2} + 3 x + 14 = 0

x = - \frac{3}{2} + i \frac{47}{2}, x = - \frac{3}{2} - i \frac{47}{2}

Solution steps

x^{2} + 3 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

Simplify

3^{2} - 4 \cdot 1 \cdot 14 : 47 i

x_{1, 2} = \frac{- 3 \pm 47 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 47 i}{2 \cdot 1}, x_{2} = \frac{- 3 - 47 i}{2 \cdot 1}

x = \frac{- 3 + 47 i}{2 \cdot 1} : - \frac{3}{2} + i \frac{47}{2}

x = \frac{- 3 - 47 i}{2 \cdot 1} : - \frac{3}{2} - i \frac{47}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2} + i \frac{47}{2}, x = - \frac{3}{2} - i \frac{47}{2}

x, x^{2} + y^{2} + 4 = 0

3 (x - 2)^{2} = 0

x, x^{2} + y^{2} + 9 = 0

(0.75 \cdot 1 0^{4}) x = (- 3000 x + 15 - 1)^{2}

4 v^{2} = - 12 v - 5

What are the solutions to the equation x^2+3x+14=0 ?
The solutions to the equation x^2+3x+14=0 are x=-3/2+i(sqrt(47))/2 ,x=-3/2-i(sqrt(47))/2
Find the zeros of x^2+3x+14=0
The zeros of x^2+3x+14=0 are x=-3/2+i(sqrt(47))/2 ,x=-3/2-i(sqrt(47))/2