What are the solutions to the equation k^2+8k+22=66 ?

The solutions to the equation k^2+8k+22=66 are k=2(sqrt(15)-2),k=-2(2+sqrt(15))

Find the zeros of k^2+8k+22=66

The zeros of k^2+8k+22=66 are k=2(sqrt(15)-2),k=-2(2+sqrt(15))

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k^{2} + 8 k + 22 = 66

k = 2 (15 - 2), k = - 2 (2 + 15)

Solution steps

k^{2} + 8 k + 22 = 66

Move

66

to the left side

k^{2} + 8 k - 44 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 44 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 44) = 415

k_{1, 2} = \frac{- 8 \pm 4 15}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 8 + 4 15}{2 \cdot 1}, k_{2} = \frac{- 8 - 4 15}{2 \cdot 1}

k = \frac{- 8 + 4 15}{2 \cdot 1} : 2 (15 - 2)

k = \frac{- 8 - 4 15}{2 \cdot 1} : - 2 (2 + 15)

The solutions to the quadratic equation are:

k = 2 (15 - 2), k = - 2 (2 + 15)

- 20 x^{2} - 27 x - 9 = 0

a, (x^{2} + y^{2} + z^{2}) = a^{2} z^{4}

x^{2} + x - 7 = - 2 x

2 x^{2} - 3 x = 0

x^{2} + 16 x - 48 = 0

What are the solutions to the equation k^2+8k+22=66 ?
The solutions to the equation k^2+8k+22=66 are k=2(sqrt(15)-2),k=-2(2+sqrt(15))
Find the zeros of k^2+8k+22=66
The zeros of k^2+8k+22=66 are k=2(sqrt(15)-2),k=-2(2+sqrt(15))