What are the solutions to the equation -20x^2-27x-9=0 ?

The solutions to the equation -20x^2-27x-9=0 are x=-3/4 ,x=-3/5

Find the zeros of -20x^2-27x-9=0

The zeros of -20x^2-27x-9=0 are x=-3/4 ,x=-3/5

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- 20 x^{2} - 27 x - 9 = 0

x = - \frac{3}{4}, x = - \frac{3}{5}

Solution steps

- 20 x^{2} - 27 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 ( - 20 ) ( - 9 )}{2 ( - 20 )}

(- 27)^{2} - 4 (- 20) (- 9) = 3

x_{1, 2} = \frac{- ( - 27 ) \pm 3}{2 ( - 20 )}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 3}{2 ( - 20 )}, x_{2} = \frac{- ( - 27 ) - 3}{2 ( - 20 )}

x = \frac{- ( - 27 ) + 3}{2 ( - 20 )} : - \frac{3}{4}

x = \frac{- ( - 27 ) - 3}{2 ( - 20 )} : - \frac{3}{5}

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - \frac{3}{5}

a, (x^{2} + y^{2} + z^{2}) = a^{2} z^{4}

x^{2} + x - 7 = - 2 x

2 x^{2} - 3 x = 0

x^{2} + 16 x - 48 = 0

2 x^{2} - x + 55 = 0

What are the solutions to the equation -20x^2-27x-9=0 ?
The solutions to the equation -20x^2-27x-9=0 are x=-3/4 ,x=-3/5
Find the zeros of -20x^2-27x-9=0
The zeros of -20x^2-27x-9=0 are x=-3/4 ,x=-3/5