What are the solutions to the equation 2x^2-x+55=0 ?

The solutions to the equation 2x^2-x+55=0 are x= 1/4+i(sqrt(439))/4 ,x= 1/4-i(sqrt(439))/4

Find the zeros of 2x^2-x+55=0

The zeros of 2x^2-x+55=0 are x= 1/4+i(sqrt(439))/4 ,x= 1/4-i(sqrt(439))/4

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2 x^{2} - x + 55 = 0

x = \frac{1}{4} + i \frac{439}{4}, x = \frac{1}{4} - i \frac{439}{4}

Solution steps

2 x^{2} - x + 55 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 55}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 55 : 439 i

x_{1, 2} = \frac{- ( - 1 ) \pm 439 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 439 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 439 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 439 i}{2 \cdot 2} : \frac{1}{4} + i \frac{439}{4}

x = \frac{- ( - 1 ) - 439 i}{2 \cdot 2} : \frac{1}{4} - i \frac{439}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{439}{4}, x = \frac{1}{4} - i \frac{439}{4}

x^{2} - 16 x + 5 = 0

x^{2} + 5 x = 11

x^{2} + 4 x + 4 = 100

m^{2} + 4 m + 40 = 0

200 x - \frac{1}{4} x^{2} = 52 x + \frac{3}{4} x^{2} + 2112

What are the solutions to the equation 2x^2-x+55=0 ?
The solutions to the equation 2x^2-x+55=0 are x= 1/4+i(sqrt(439))/4 ,x= 1/4-i(sqrt(439))/4
Find the zeros of 2x^2-x+55=0
The zeros of 2x^2-x+55=0 are x= 1/4+i(sqrt(439))/4 ,x= 1/4-i(sqrt(439))/4