What are the solutions to the equation x^2+4x+4=100 ?

The solutions to the equation x^2+4x+4=100 are x=8,x=-12

Find the zeros of x^2+4x+4=100

The zeros of x^2+4x+4=100 are x=8,x=-12

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x^{2} + 4 x + 4 = 100

x = 8, x = - 12

Solution steps

x^{2} + 4 x + 4 = 100

Move

100

to the left side

x^{2} + 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 96) = 20

x_{1, 2} = \frac{- 4 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 20}{2 \cdot 1}, x_{2} = \frac{- 4 - 20}{2 \cdot 1}

x = \frac{- 4 + 20}{2 \cdot 1} : 8

x = \frac{- 4 - 20}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 8, x = - 12

m^{2} + 4 m + 40 = 0

200 x - \frac{1}{4} x^{2} = 52 x + \frac{3}{4} x^{2} + 2112

3 x^{2} - 3 = 3 x

5 x^{2} + 50 x + 45 = 0

5 x^{2} = 900

What are the solutions to the equation x^2+4x+4=100 ?
The solutions to the equation x^2+4x+4=100 are x=8,x=-12
Find the zeros of x^2+4x+4=100
The zeros of x^2+4x+4=100 are x=8,x=-12