What are the solutions to the equation 5x^2+8x=4 ?

The solutions to the equation 5x^2+8x=4 are x= 2/5 ,x=-2

Find the zeros of 5x^2+8x=4

The zeros of 5x^2+8x=4 are x= 2/5 ,x=-2

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5 x^{2} + 8 x = 4

x = \frac{2}{5}, x = - 2

Solution steps

5 x^{2} + 8 x = 4

Move

4

to the left side

5 x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

8^{2} - 4 \cdot 5 (- 4) = 12

x_{1, 2} = \frac{- 8 \pm 12}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 8 + 12}{2 \cdot 5}, x_{2} = \frac{- 8 - 12}{2 \cdot 5}

x = \frac{- 8 + 12}{2 \cdot 5} : \frac{2}{5}

x = \frac{- 8 - 12}{2 \cdot 5} : - 2

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - 2

- 3 x^{2} + 5 x = 0

3 x^{2} - 2 x = 2

- 5 x^{2} - 10 x = 0

x + 5 = x^{2} - x + 2

3 x^{2} + 6 x - 7 = 0

What are the solutions to the equation 5x^2+8x=4 ?
The solutions to the equation 5x^2+8x=4 are x= 2/5 ,x=-2
Find the zeros of 5x^2+8x=4
The zeros of 5x^2+8x=4 are x= 2/5 ,x=-2