What are the solutions to the equation 3x^2+6x-7=0 ?

The solutions to the equation 3x^2+6x-7=0 are x=(-3+sqrt(30))/3 ,x=-(3+sqrt(30))/3

Find the zeros of 3x^2+6x-7=0

The zeros of 3x^2+6x-7=0 are x=(-3+sqrt(30))/3 ,x=-(3+sqrt(30))/3

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3 x^{2} + 6 x - 7 = 0

x = \frac{- 3 + 30}{3}, x = - \frac{3 + 30}{3}

Solution steps

3 x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 7) = 230

x_{1, 2} = \frac{- 6 \pm 2 30}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 30}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 30}{2 \cdot 3}

x = \frac{- 6 + 2 30}{2 \cdot 3} : \frac{- 3 + 30}{3}

x = \frac{- 6 - 2 30}{2 \cdot 3} : - \frac{3 + 30}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 30}{3}, x = - \frac{3 + 30}{3}

m^{2} + 10 m + 16 = 0

- 2 x^{2} - 15 x - 4 = - 3 x^{2}

- 120 - 26 x = x^{2}

2 x^{2} - 22 x + 60 = 0

3 x^{2} - 23 x + 14 = 0

What are the solutions to the equation 3x^2+6x-7=0 ?
The solutions to the equation 3x^2+6x-7=0 are x=(-3+sqrt(30))/3 ,x=-(3+sqrt(30))/3
Find the zeros of 3x^2+6x-7=0
The zeros of 3x^2+6x-7=0 are x=(-3+sqrt(30))/3 ,x=-(3+sqrt(30))/3