What are the solutions to the equation m^2+10m+16=0 ?

The solutions to the equation m^2+10m+16=0 are m=-2,m=-8

Find the zeros of m^2+10m+16=0

The zeros of m^2+10m+16=0 are m=-2,m=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

m^{2} + 10 m + 16 = 0

m = - 2, m = - 8

Solution steps

m^{2} + 10 m + 16 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 16 = 6

m_{1, 2} = \frac{- 10 \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 10 + 6}{2 \cdot 1}, m_{2} = \frac{- 10 - 6}{2 \cdot 1}

m = \frac{- 10 + 6}{2 \cdot 1} : - 2

m = \frac{- 10 - 6}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

m = - 2, m = - 8

- 2 x^{2} - 15 x - 4 = - 3 x^{2}

- 120 - 26 x = x^{2}

2 x^{2} - 22 x + 60 = 0

3 x^{2} - 23 x + 14 = 0

72 x^{2} - 12 x - 24 = 0

What are the solutions to the equation m^2+10m+16=0 ?
The solutions to the equation m^2+10m+16=0 are m=-2,m=-8
Find the zeros of m^2+10m+16=0
The zeros of m^2+10m+16=0 are m=-2,m=-8