What are the solutions to the equation s^2+8s+8=0 ?

The solutions to the equation s^2+8s+8=0 are s=2(sqrt(2)-2),s=-2(2+sqrt(2))

Find the zeros of s^2+8s+8=0

The zeros of s^2+8s+8=0 are s=2(sqrt(2)-2),s=-2(2+sqrt(2))

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s^{2} + 8 s + 8 = 0

s = 2 (2 - 2), s = - 2 (2 + 2)

Solution steps

s^{2} + 8 s + 8 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 8 = 42

s_{1, 2} = \frac{- 8 \pm 4 2}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 8 + 4 2}{2 \cdot 1}, s_{2} = \frac{- 8 - 4 2}{2 \cdot 1}

s = \frac{- 8 + 4 2}{2 \cdot 1} : 2 (2 - 2)

s = \frac{- 8 - 4 2}{2 \cdot 1} : - 2 (2 + 2)

The solutions to the quadratic equation are:

s = 2 (2 - 2), s = - 2 (2 + 2)

15 x^{2} + 34 x - 77 = 0

3 x^{1} + 6 x^{2} = 9, - 2 x^{1} + 3 x^{2} = 4

\frac{x ^{2} - x}{2} - \frac{( x - 4 ) ^{2}}{3} = 0

- 0.45 x^{2} + 5.52 x - 13.7 = 0

x, z = 4 (x - y) - x^{2} - y^{2}

What are the solutions to the equation s^2+8s+8=0 ?
The solutions to the equation s^2+8s+8=0 are s=2(sqrt(2)-2),s=-2(2+sqrt(2))
Find the zeros of s^2+8s+8=0
The zeros of s^2+8s+8=0 are s=2(sqrt(2)-2),s=-2(2+sqrt(2))