What are the solutions to the equation -14x+21-7x^2=0 ?

The solutions to the equation -14x+21-7x^2=0 are x=-3,x=1

Find the zeros of -14x+21-7x^2=0

The zeros of -14x+21-7x^2=0 are x=-3,x=1

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- 14 x + 21 - 7 x^{2} = 0

x = - 3, x = 1

Solution steps

- 14 x + 21 - 7 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 7 x^{2} - 14 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 ( - 7 ) \cdot 21}{2 ( - 7 )}

(- 14)^{2} - 4 (- 7) \cdot 21 = 28

x_{1, 2} = \frac{- ( - 14 ) \pm 28}{2 ( - 7 )}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 28}{2 ( - 7 )}, x_{2} = \frac{- ( - 14 ) - 28}{2 ( - 7 )}

x = \frac{- ( - 14 ) + 28}{2 ( - 7 )} : - 3

x = \frac{- ( - 14 ) - 28}{2 ( - 7 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

x, f = x^{2} + 2 k x + k

- 3 x^{2} + 18 x = - 30

6 - x^{2} = 0

x^{2} + 8 x + 15

x^{2} + m x + n = 0

What are the solutions to the equation -14x+21-7x^2=0 ?
The solutions to the equation -14x+21-7x^2=0 are x=-3,x=1
Find the zeros of -14x+21-7x^2=0
The zeros of -14x+21-7x^2=0 are x=-3,x=1