What are the solutions to the equation 3(x-4)^2=2(x-4) ?

The solutions to the equation 3(x-4)^2=2(x-4) are x=4,x= 14/3

Find the zeros of 3(x-4)^2=2(x-4)

The zeros of 3(x-4)^2=2(x-4) are x=4,x= 14/3

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3 (x - 4)^{2} = 2 (x - 4)

x = 4, x = \frac{14}{3}

Solution steps

3 (x - 4)^{2} = 2 (x - 4)

Move

2 (x - 4)

to the left side

3 (x - 4)^{2} - 2 (x - 4) = 0

Factor

3 (x - 4)^{2} - 2 (x - 4) : (x - 4) (3 x - 14)

(x - 4) (3 x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or 3 x - 14 = 0

Solve

x - 4 = 0 : x = 4

Solve

3 x - 14 = 0 : x = \frac{14}{3}

The solutions to the quadratic equation are:

x = 4, x = \frac{14}{3}

z^{2} - 0.75 z + 0.125 = 0

5 = (x - 3)^{2}

x^{2} = a^{2} + a^{2}

x^{2} + 3^{2} = 8^{2}

x^{2} + 13 x + 15 = 0

What are the solutions to the equation 3(x-4)^2=2(x-4) ?
The solutions to the equation 3(x-4)^2=2(x-4) are x=4,x= 14/3
Find the zeros of 3(x-4)^2=2(x-4)
The zeros of 3(x-4)^2=2(x-4) are x=4,x= 14/3