What are the solutions to the equation 0=-x^2+6x-5 ?

The solutions to the equation 0=-x^2+6x-5 are x=1,x=5

Find the zeros of 0=-x^2+6x-5

The zeros of 0=-x^2+6x-5 are x=1,x=5

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0 = - x^{2} + 6 x - 5

x = 1, x = 5

Solution steps

0 = - x^{2} + 6 x - 5

Switch sides

- x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 5 )}{2 ( - 1 )}

6^{2} - 4 (- 1) (- 5) = 4

x_{1, 2} = \frac{- 6 \pm 4}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 4}{2 ( - 1 )}, x_{2} = \frac{- 6 - 4}{2 ( - 1 )}

x = \frac{- 6 + 4}{2 ( - 1 )} : 1

x = \frac{- 6 - 4}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = 1, x = 5

x^{2} = 91

x^{2} = 85

4 x - x^{2} = 1

3 x^{2} + 10 x - 4 = 0

- x^{2} - x + 42 = 0

What are the solutions to the equation 0=-x^2+6x-5 ?
The solutions to the equation 0=-x^2+6x-5 are x=1,x=5
Find the zeros of 0=-x^2+6x-5
The zeros of 0=-x^2+6x-5 are x=1,x=5