What are the solutions to the equation 3x^2+10x-4=0 ?

The solutions to the equation 3x^2+10x-4=0 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3

Find the zeros of 3x^2+10x-4=0

The zeros of 3x^2+10x-4=0 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3

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3 x^{2} + 10 x - 4 = 0

x = \frac{- 5 + 37}{3}, x = - \frac{5 + 37}{3}

Solution steps

3 x^{2} + 10 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

1 0^{2} - 4 \cdot 3 (- 4) = 237

x_{1, 2} = \frac{- 10 \pm 2 37}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 10 + 2 37}{2 \cdot 3}, x_{2} = \frac{- 10 - 2 37}{2 \cdot 3}

x = \frac{- 10 + 2 37}{2 \cdot 3} : \frac{- 5 + 37}{3}

x = \frac{- 10 - 2 37}{2 \cdot 3} : - \frac{5 + 37}{3}

The solutions to the quadratic equation are:

x = \frac{- 5 + 37}{3}, x = - \frac{5 + 37}{3}

- x^{2} - x + 42 = 0

(x - 3)^{2} - 2 (x - 3) + 1 = 0

- 0.001 x^{2} - 0.4 x + 210 = 0.0006 x^{2} + 0.26 x + 128

(x + 3)^{2} - 9 = 7

(1 - x)^{2} - 9 = 0

What are the solutions to the equation 3x^2+10x-4=0 ?
The solutions to the equation 3x^2+10x-4=0 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3
Find the zeros of 3x^2+10x-4=0
The zeros of 3x^2+10x-4=0 are x=(-5+sqrt(37))/3 ,x=-(5+sqrt(37))/3