What are the solutions to the equation (x+3)^2-9=7 ?

The solutions to the equation (x+3)^2-9=7 are x=1,x=-7

Find the zeros of (x+3)^2-9=7

The zeros of (x+3)^2-9=7 are x=1,x=-7

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(x + 3)^{2} - 9 = 7

x = 1, x = - 7

Solution steps

(x + 3)^{2} - 9 = 7

Move

9

to the right side

(x + 3)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 16 : x = 1

Solve

x + 3 = - 16 : x = - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

x^{2} + 6 x - 16 = 0

(1 - x)^{2} - 9 = 0

(x + 3)^{2} - 5 = 0

- 2 x^{2} + 4 x - 5 = 0

- 4 x^{2} + 3 x + 5 = 0

What are the solutions to the equation (x+3)^2-9=7 ?
The solutions to the equation (x+3)^2-9=7 are x=1,x=-7
Find the zeros of (x+3)^2-9=7
The zeros of (x+3)^2-9=7 are x=1,x=-7