What are the solutions to the equation -4x^2+3x+5=0 ?

The solutions to the equation -4x^2+3x+5=0 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8

Find the zeros of -4x^2+3x+5=0

The zeros of -4x^2+3x+5=0 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8

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- 4 x^{2} + 3 x + 5 = 0

x = - \frac{- 3 + 89}{8}, x = \frac{3 + 89}{8}

Solution steps

- 4 x^{2} + 3 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 5 = 89

x_{1, 2} = \frac{- 3 \pm 89}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 89}{2 ( - 4 )}, x_{2} = \frac{- 3 - 89}{2 ( - 4 )}

x = \frac{- 3 + 89}{2 ( - 4 )} : - \frac{- 3 + 89}{8}

x = \frac{- 3 - 89}{2 ( - 4 )} : \frac{3 + 89}{8}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 89}{8}, x = \frac{3 + 89}{8}

3 x^{2} + 10 x - 3 = 0

\frac{( y - 6 ) ^{2}}{4 ^{2}} - \frac{( 0 - 2 ) ^{2}}{3 ^{2}} = 1

- 5 x^{2} - 10 x - 130 = 0

x (x - 3) = 2 (x + 7)

x, x^{2} y^{2} - 2 x = 4 - 4 y

What are the solutions to the equation -4x^2+3x+5=0 ?
The solutions to the equation -4x^2+3x+5=0 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8
Find the zeros of -4x^2+3x+5=0
The zeros of -4x^2+3x+5=0 are x=-(-3+sqrt(89))/8 ,x=(3+sqrt(89))/8