What are the solutions to the equation -5x^2-10x-130=0 ?

The solutions to the equation -5x^2-10x-130=0 are x=-1-5i,x=-1+5i

Find the zeros of -5x^2-10x-130=0

The zeros of -5x^2-10x-130=0 are x=-1-5i,x=-1+5i

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- 5 x^{2} - 10 x - 130 = 0

x = - 1 - 5 i, x = - 1 + 5 i

Solution steps

- 5 x^{2} - 10 x - 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 ( - 5 ) ( - 130 )}{2 ( - 5 )}

Simplify

(- 10)^{2} - 4 (- 5) (- 130) : 50 i

x_{1, 2} = \frac{- ( - 10 ) \pm 50 i}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 50 i}{2 ( - 5 )}, x_{2} = \frac{- ( - 10 ) - 50 i}{2 ( - 5 )}

x = \frac{- ( - 10 ) + 50 i}{2 ( - 5 )} : - 1 - 5 i

x = \frac{- ( - 10 ) - 50 i}{2 ( - 5 )} : - 1 + 5 i

The solutions to the quadratic equation are:

x = - 1 - 5 i, x = - 1 + 5 i

x (x - 3) = 2 (x + 7)

x, x^{2} y^{2} - 2 x = 4 - 4 y

x^{2} + 10 x + 30

144 - 96 x + 12 x^{2} = 0

x, x^{2} = 1

What are the solutions to the equation -5x^2-10x-130=0 ?
The solutions to the equation -5x^2-10x-130=0 are x=-1-5i,x=-1+5i
Find the zeros of -5x^2-10x-130=0
The zeros of -5x^2-10x-130=0 are x=-1-5i,x=-1+5i