What are the solutions to the equation 144-96x+12x^2=0 ?

The solutions to the equation 144-96x+12x^2=0 are x=6,x=2

Find the zeros of 144-96x+12x^2=0

The zeros of 144-96x+12x^2=0 are x=6,x=2

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144 - 96 x + 12 x^{2} = 0

x = 6, x = 2

Solution steps

144 - 96 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 96 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 12 \cdot 144}{2 \cdot 12}

(- 96)^{2} - 4 \cdot 12 \cdot 144 = 48

x_{1, 2} = \frac{- ( - 96 ) \pm 48}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 48}{2 \cdot 12}, x_{2} = \frac{- ( - 96 ) - 48}{2 \cdot 12}

x = \frac{- ( - 96 ) + 48}{2 \cdot 12} : 6

x = \frac{- ( - 96 ) - 48}{2 \cdot 12} : 2

The solutions to the quadratic equation are:

x = 6, x = 2

x, x^{2} = 1

5 (x - 7)^{2} = 135

6 x^{2} - 7 x = 5

x^{2} - 25 = 75

8 x^{2} + 2 x = 15

What are the solutions to the equation 144-96x+12x^2=0 ?
The solutions to the equation 144-96x+12x^2=0 are x=6,x=2
Find the zeros of 144-96x+12x^2=0
The zeros of 144-96x+12x^2=0 are x=6,x=2