What are the solutions to the equation 6x^2-7x=5 ?

The solutions to the equation 6x^2-7x=5 are x= 5/3 ,x=-1/2

Find the zeros of 6x^2-7x=5

The zeros of 6x^2-7x=5 are x= 5/3 ,x=-1/2

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6 x^{2} - 7 x = 5

x = \frac{5}{3}, x = - \frac{1}{2}

Solution steps

6 x^{2} - 7 x = 5

Move

5

to the left side

6 x^{2} - 7 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 6 ( - 5 )}{2 \cdot 6}

(- 7)^{2} - 4 \cdot 6 (- 5) = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 6}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 6}

x = \frac{- ( - 7 ) + 13}{2 \cdot 6} : \frac{5}{3}

x = \frac{- ( - 7 ) - 13}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{1}{2}

x^{2} - 25 = 75

8 x^{2} + 2 x = 15

a^{2} + 2 a - 3 = 0

x, g = x^{2} + y^{2} + z^{2}

x^{2} + 18 x + 67 = 0

What are the solutions to the equation 6x^2-7x=5 ?
The solutions to the equation 6x^2-7x=5 are x= 5/3 ,x=-1/2
Find the zeros of 6x^2-7x=5
The zeros of 6x^2-7x=5 are x= 5/3 ,x=-1/2