What are the solutions to the equation 8x^2+2x=15 ?

The solutions to the equation 8x^2+2x=15 are x= 5/4 ,x=-3/2

Find the zeros of 8x^2+2x=15

The zeros of 8x^2+2x=15 are x= 5/4 ,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

8 x^{2} + 2 x = 15

x = \frac{5}{4}, x = - \frac{3}{2}

Solution steps

8 x^{2} + 2 x = 15

Move

15

to the left side

8 x^{2} + 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 15) = 22

x_{1, 2} = \frac{- 2 \pm 22}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 2 + 22}{2 \cdot 8}, x_{2} = \frac{- 2 - 22}{2 \cdot 8}

x = \frac{- 2 + 22}{2 \cdot 8} : \frac{5}{4}

x = \frac{- 2 - 22}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = - \frac{3}{2}

a^{2} + 2 a - 3 = 0

x, g = x^{2} + y^{2} + z^{2}

x^{2} + 18 x + 67 = 0

(x - 7)^{2} = 7

1.2 x^{2} + 5 x = 3

What are the solutions to the equation 8x^2+2x=15 ?
The solutions to the equation 8x^2+2x=15 are x= 5/4 ,x=-3/2
Find the zeros of 8x^2+2x=15
The zeros of 8x^2+2x=15 are x= 5/4 ,x=-3/2