What are the solutions to the equation x^2+18x+67=0 ?

The solutions to the equation x^2+18x+67=0 are x=-9+sqrt(14),x=-9-sqrt(14)

Find the zeros of x^2+18x+67=0

The zeros of x^2+18x+67=0 are x=-9+sqrt(14),x=-9-sqrt(14)

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x^{2} + 18 x + 67 = 0

x = - 9 + 14, x = - 9 - 14

Solution steps

x^{2} + 18 x + 67 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 67}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 67 = 214

x_{1, 2} = \frac{- 18 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 14}{2 \cdot 1}

x = \frac{- 18 + 2 14}{2 \cdot 1} : - 9 + 14

x = \frac{- 18 - 2 14}{2 \cdot 1} : - 9 - 14

The solutions to the quadratic equation are:

x = - 9 + 14, x = - 9 - 14

(x - 7)^{2} = 7

1.2 x^{2} + 5 x = 3

(8 - d)^{2} + 81 = 100

(x + 1)^{2} = 2 x^{2}

0 = - x^{2}

What are the solutions to the equation x^2+18x+67=0 ?
The solutions to the equation x^2+18x+67=0 are x=-9+sqrt(14),x=-9-sqrt(14)
Find the zeros of x^2+18x+67=0
The zeros of x^2+18x+67=0 are x=-9+sqrt(14),x=-9-sqrt(14)