What are the solutions to the equation x^2+17x-18=-10 ?

The solutions to the equation x^2+17x-18=-10 are x=(-17+sqrt(321))/2 ,x=(-17-sqrt(321))/2

Find the zeros of x^2+17x-18=-10

The zeros of x^2+17x-18=-10 are x=(-17+sqrt(321))/2 ,x=(-17-sqrt(321))/2

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x^{2} + 17 x - 18 = - 10

x = \frac{- 17 + 321}{2}, x = \frac{- 17 - 321}{2}

Solution steps

x^{2} + 17 x - 18 = - 10

Move

10

to the left side

x^{2} + 17 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot (- 8) = 321

x_{1, 2} = \frac{- 17 \pm 321}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 321}{2 \cdot 1}, x_{2} = \frac{- 17 - 321}{2 \cdot 1}

x = \frac{- 17 + 321}{2 \cdot 1} : \frac{- 17 + 321}{2}

x = \frac{- 17 - 321}{2 \cdot 1} : \frac{- 17 - 321}{2}

The solutions to the quadratic equation are:

x = \frac{- 17 + 321}{2}, x = \frac{- 17 - 321}{2}

2 x^{2} + 7 x + 8 = 0

5 d (3 d + 2) = 0

9 - x^{2} = x + 1

x^{2} - x = 0

b x^{2} + 5 = 6

What are the solutions to the equation x^2+17x-18=-10 ?
The solutions to the equation x^2+17x-18=-10 are x=(-17+sqrt(321))/2 ,x=(-17-sqrt(321))/2
Find the zeros of x^2+17x-18=-10
The zeros of x^2+17x-18=-10 are x=(-17+sqrt(321))/2 ,x=(-17-sqrt(321))/2