What are the solutions to the equation 8c^2+2c-1=0 ?

The solutions to the equation 8c^2+2c-1=0 are c= 1/4 ,c=-1/2

Find the zeros of 8c^2+2c-1=0

The zeros of 8c^2+2c-1=0 are c= 1/4 ,c=-1/2

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8 c^{2} + 2 c - 1 = 0

c = \frac{1}{4}, c = - \frac{1}{2}

Solution steps

8 c^{2} + 2 c - 1 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 8 ( - 1 )}{2 \cdot 8}

2^{2} - 4 \cdot 8 (- 1) = 6

c_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 8}

Separate the solutions

c_{1} = \frac{- 2 + 6}{2 \cdot 8}, c_{2} = \frac{- 2 - 6}{2 \cdot 8}

c = \frac{- 2 + 6}{2 \cdot 8} : \frac{1}{4}

c = \frac{- 2 - 6}{2 \cdot 8} : - \frac{1}{2}

The solutions to the quadratic equation are:

c = \frac{1}{4}, c = - \frac{1}{2}

x^{2} - 10 x = 6

2 m^{2} + 2 m - 24 = 0

- x^{2} = 5

x^{2} + \frac{2}{3} x + 1

x^{2} - 5 x - 36 = 0

What are the solutions to the equation 8c^2+2c-1=0 ?
The solutions to the equation 8c^2+2c-1=0 are c= 1/4 ,c=-1/2
Find the zeros of 8c^2+2c-1=0
The zeros of 8c^2+2c-1=0 are c= 1/4 ,c=-1/2