What are the solutions to the equation x^2-3x=6 ?

The solutions to the equation x^2-3x=6 are x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2

Find the zeros of x^2-3x=6

The zeros of x^2-3x=6 are x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2

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x^{2} - 3 x = 6

x = \frac{3 + 33}{2}, x = \frac{3 - 33}{2}

Decimal Notation

x = 4.37228 \dots, x = - 1.37228 \dots

Solution steps

x^{2} - 3 x = 6

Move

6

to the left side

x^{2} - 3 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 6) = 33

x_{1, 2} = \frac{- ( - 3 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 33}{2 \cdot 1}

x = \frac{- ( - 3 ) + 33}{2 \cdot 1} : \frac{3 + 33}{2}

x = \frac{- ( - 3 ) - 33}{2 \cdot 1} : \frac{3 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 33}{2}, x = \frac{3 - 33}{2}

x^{2} - 4 x - 5 = 0

x^{2} + 26 x

- 10 x^{2} + x + 11 = 0

8 x^{2} + 32 x = 0

8^{2} + b^{2} = 1 0^{2}

What are the solutions to the equation x^2-3x=6 ?
The solutions to the equation x^2-3x=6 are x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2
Find the zeros of x^2-3x=6
The zeros of x^2-3x=6 are x=(3+sqrt(33))/2 ,x=(3-sqrt(33))/2