What are the solutions to the equation -10x^2+x+11=0 ?

The solutions to the equation -10x^2+x+11=0 are x=-1,x= 11/10

Find the zeros of -10x^2+x+11=0

The zeros of -10x^2+x+11=0 are x=-1,x= 11/10

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- 10 x^{2} + x + 11 = 0

x = - 1, x = \frac{11}{10}

Decimal Notation

x = - 1, x = 1.1

Solution steps

- 10 x^{2} + x + 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 10 ) \cdot 11}{2 ( - 10 )}

1^{2} - 4 (- 10) \cdot 11 = 21

x_{1, 2} = \frac{- 1 \pm 21}{2 ( - 10 )}

Separate the solutions

x_{1} = \frac{- 1 + 21}{2 ( - 10 )}, x_{2} = \frac{- 1 - 21}{2 ( - 10 )}

x = \frac{- 1 + 21}{2 ( - 10 )} : - 1

x = \frac{- 1 - 21}{2 ( - 10 )} : \frac{11}{10}

The solutions to the quadratic equation are:

x = - 1, x = \frac{11}{10}

8 x^{2} + 32 x = 0

8^{2} + b^{2} = 1 0^{2}

14 x^{2} - 33 x - 5 = 0

x^{2} + 4 x = 17

w^{2} + 11 w + 28 = 0

What are the solutions to the equation -10x^2+x+11=0 ?
The solutions to the equation -10x^2+x+11=0 are x=-1,x= 11/10
Find the zeros of -10x^2+x+11=0
The zeros of -10x^2+x+11=0 are x=-1,x= 11/10