What are the solutions to the equation factor 14x^2-33x-5=0 ?

The solutions to the equation factor 14x^2-33x-5=0 are x=-1/7 ,x= 5/2

Find the zeros of factor 14x^2-33x-5=0

The zeros of factor 14x^2-33x-5=0 are x=-1/7 ,x= 5/2

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14 x^{2} - 33 x - 5 = 0

x = - \frac{1}{7}, x = \frac{5}{2}

Solution steps

14 x^{2} - 33 x - 5 = 0

Factor

14 x^{2} - 33 x - 5 : (7 x + 1) (2 x - 5)

(7 x + 1) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

7 x + 1 = 0 or 2 x - 5 = 0

Solve

7 x + 1 = 0 : x = - \frac{1}{7}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{7}, x = \frac{5}{2}

x^{2} + 4 x = 17

w^{2} + 11 w + 28 = 0

0 = - 16 t^{2} + 160 t

320 = - 20 x^{2} + 320 x - 780

t^{2} + 2 t = 15

What are the solutions to the equation factor 14x^2-33x-5=0 ?
The solutions to the equation factor 14x^2-33x-5=0 are x=-1/7 ,x= 5/2
Find the zeros of factor 14x^2-33x-5=0
The zeros of factor 14x^2-33x-5=0 are x=-1/7 ,x= 5/2