What are the solutions to the equation h^2-10h-4=0 ?

The solutions to the equation h^2-10h-4=0 are h=5+sqrt(29),h=5-sqrt(29)

Find the zeros of h^2-10h-4=0

The zeros of h^2-10h-4=0 are h=5+sqrt(29),h=5-sqrt(29)

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h^{2} - 10 h - 4 = 0

h = 5 + 29, h = 5 - 29

Decimal Notation

h = 10.38516 \dots, h = - 0.38516 \dots

Solution steps

h^{2} - 10 h - 4 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 4) = 229

h_{1, 2} = \frac{- ( - 10 ) \pm 2 29}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 10 ) + 2 29}{2 \cdot 1}, h_{2} = \frac{- ( - 10 ) - 2 29}{2 \cdot 1}

h = \frac{- ( - 10 ) + 2 29}{2 \cdot 1} : 5 + 29

h = \frac{- ( - 10 ) - 2 29}{2 \cdot 1} : 5 - 29

The solutions to the quadratic equation are:

h = 5 + 29, h = 5 - 29

- x^{2} + 320 x - 25.6 = 0

x^{2} + 8 x + 80 = 0

x^{2} - 2 x - 2 = 0

12 x^{2} + 3 x - 5 = 0

4 x^{2} + 10 x - 3 = 0

What are the solutions to the equation h^2-10h-4=0 ?
The solutions to the equation h^2-10h-4=0 are h=5+sqrt(29),h=5-sqrt(29)
Find the zeros of h^2-10h-4=0
The zeros of h^2-10h-4=0 are h=5+sqrt(29),h=5-sqrt(29)