What are the solutions to the equation completesquare 4x^2+10x-3=0 ?

The solutions to the equation completesquare 4x^2+10x-3=0 are x=(sqrt(37)-5)/4 ,x=(-sqrt(37)-5)/4

Find the zeros of completesquare 4x^2+10x-3=0

The zeros of completesquare 4x^2+10x-3=0 are x=(sqrt(37)-5)/4 ,x=(-sqrt(37)-5)/4

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4 x^{2} + 10 x - 3 = 0

x = \frac{37 - 5}{4}, x = \frac{- 37 - 5}{4}

Decimal Notation

x = 0.27069 \dots, x = - 2.77069 \dots

Solution steps

4 x^{2} + 10 x - 3 = 0

Move

3

to the right side

4 x^{2} + 10 x = 3

Divide both sides by

4

\frac{4 x ^{2} + 10 x}{4} = \frac{3}{4}

x^{2} + \frac{5 x}{2} = \frac{3}{4}

Rewrite in the form

(x + a)^{2} = b

(x + \frac{5}{4})^{2} = \frac{37}{16}

For

the solutions are

f (x) = a, - a

Solve

x + \frac{5}{4} = \frac{37}{16} : x = \frac{37 - 5}{4}

Solve

x + \frac{5}{4} = - \frac{37}{16} : x = \frac{- 37 - 5}{4}

The solutions to the quadratic equation are:

x = \frac{37 - 5}{4}, x = \frac{- 37 - 5}{4}

x^{2} + 6 x + 21 = 0

x^{2} = 7 (\frac{4}{5} x - 10)

1 5^{2} + 2 0^{2} = c^{2}

x^{2} - 12 x + 19 = 0

4 x + x^{2} + 16 = - 4 x^{2}

What are the solutions to the equation completesquare 4x^2+10x-3=0 ?
The solutions to the equation completesquare 4x^2+10x-3=0 are x=(sqrt(37)-5)/4 ,x=(-sqrt(37)-5)/4
Find the zeros of completesquare 4x^2+10x-3=0
The zeros of completesquare 4x^2+10x-3=0 are x=(sqrt(37)-5)/4 ,x=(-sqrt(37)-5)/4