What are the solutions to the equation x^2-12x+19=0 ?

The solutions to the equation x^2-12x+19=0 are x=6+sqrt(17),x=6-sqrt(17)

Find the zeros of x^2-12x+19=0

The zeros of x^2-12x+19=0 are x=6+sqrt(17),x=6-sqrt(17)

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x^{2} - 12 x + 19 = 0

x = 6 + 17, x = 6 - 17

Decimal Notation

x = 10.12310 \dots, x = 1.87689 \dots

Solution steps

x^{2} - 12 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 19 = 217

x_{1, 2} = \frac{- ( - 12 ) \pm 2 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 17}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 17}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 17}{2 \cdot 1} : 6 + 17

x = \frac{- ( - 12 ) - 2 17}{2 \cdot 1} : 6 - 17

The solutions to the quadratic equation are:

x = 6 + 17, x = 6 - 17

4 x + x^{2} + 16 = - 4 x^{2}

x^{2} - 3.2 x + 1.35 = 0

x, 3 x^{2} - 27 = 0

x, f = x^{2} + 2 y

(y - 4)^{2} = 8 (y - 2)

What are the solutions to the equation x^2-12x+19=0 ?
The solutions to the equation x^2-12x+19=0 are x=6+sqrt(17),x=6-sqrt(17)
Find the zeros of x^2-12x+19=0
The zeros of x^2-12x+19=0 are x=6+sqrt(17),x=6-sqrt(17)