What are the solutions to the equation x^2-3.2x+1.35=0 ?

The solutions to the equation x^2-3.2x+1.35=0 are x= 27/10 ,x= 1/2

Find the zeros of x^2-3.2x+1.35=0

The zeros of x^2-3.2x+1.35=0 are x= 27/10 ,x= 1/2

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x^{2} - 3.2 x + 1.35 = 0

x = \frac{27}{10}, x = \frac{1}{2}

Decimal Notation

x = 2.7, x = 0.5

Solution steps

x^{2} - 3.2 x + 1.35 = 0

Multiply both sides by

100

100 x^{2} - 320 x + 135 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 320 ) \pm ( - 320 ) ^{2} - 4 \cdot 100 \cdot 135}{2 \cdot 100}

(- 320)^{2} - 4 \cdot 100 \cdot 135 = 220

x_{1, 2} = \frac{- ( - 320 ) \pm 220}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 320 ) + 220}{2 \cdot 100}, x_{2} = \frac{- ( - 320 ) - 220}{2 \cdot 100}

x = \frac{- ( - 320 ) + 220}{2 \cdot 100} : \frac{27}{10}

x = \frac{- ( - 320 ) - 220}{2 \cdot 100} : \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{27}{10}, x = \frac{1}{2}

x, 3 x^{2} - 27 = 0

x, f = x^{2} + 2 y

(y - 4)^{2} = 8 (y - 2)

m^{2} - 14 m - 239 = 0

\frac{x ^{2}}{4} + \frac{3 x}{2} + 2 = 0

What are the solutions to the equation x^2-3.2x+1.35=0 ?
The solutions to the equation x^2-3.2x+1.35=0 are x= 27/10 ,x= 1/2
Find the zeros of x^2-3.2x+1.35=0
The zeros of x^2-3.2x+1.35=0 are x= 27/10 ,x= 1/2