What are the solutions to the equation (x^2)/4+(3x)/2+2=0 ?

The solutions to the equation (x^2)/4+(3x)/2+2=0 are x=-2,x=-4

Find the zeros of (x^2)/4+(3x)/2+2=0

The zeros of (x^2)/4+(3x)/2+2=0 are x=-2,x=-4

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\frac{x ^{2}}{4} + \frac{3 x}{2} + 2 = 0

x = - 2, x = - 4

Solution steps

\frac{x ^{2}}{4} + \frac{3 x}{2} + 2 = 0

Find Least Common Multiplier of

4, 2 : 4

Multiply by LCM=

4

\frac{x ^{2}}{4} \cdot 4 + \frac{3 x}{2} \cdot 4 + 2 \cdot 4 = 0 \cdot 4

Simplify

x^{2} + 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- 6 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2}{2 \cdot 1}, x_{2} = \frac{- 6 - 2}{2 \cdot 1}

x = \frac{- 6 + 2}{2 \cdot 1} : - 2

x = \frac{- 6 - 2}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

4 x^{2} + 6 x + 7 = 0

x^{2} + 100 = 20 x

x^{2} - 7 x + 29 = 3 x + 4

(x - 5)^{2} + 7 (x - 5) + 10 = 0

4 x^{2} - 24 x + 32 = 0

What are the solutions to the equation (x^2)/4+(3x)/2+2=0 ?
The solutions to the equation (x^2)/4+(3x)/2+2=0 are x=-2,x=-4
Find the zeros of (x^2)/4+(3x)/2+2=0
The zeros of (x^2)/4+(3x)/2+2=0 are x=-2,x=-4