What are the solutions to the equation x^2-7x+29=3x+4 ?

The solutions to the equation x^2-7x+29=3x+4 are x=5

Find the zeros of x^2-7x+29=3x+4

The zeros of x^2-7x+29=3x+4 are x=5

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x^{2} - 7 x + 29 = 3 x + 4

x = 5

Solution steps

x^{2} - 7 x + 29 = 3 x + 4

Move

4

to the left side

x^{2} - 7 x + 25 = 3 x

Move

3 x

to the left side

x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

x = 5

The solution to the quadratic equation is:

x = 5

(x - 5)^{2} + 7 (x - 5) + 10 = 0

4 x^{2} - 24 x + 32 = 0

16 x^{2} - 8 x = 0

3 y^{2} + 12 y + 12 = 0

18 x^{2} - 12 x = 0

What are the solutions to the equation x^2-7x+29=3x+4 ?
The solutions to the equation x^2-7x+29=3x+4 are x=5
Find the zeros of x^2-7x+29=3x+4
The zeros of x^2-7x+29=3x+4 are x=5