What are the solutions to the equation (x-5)^2+7(x-5)+10=0 ?

The solutions to the equation (x-5)^2+7(x-5)+10=0 are x=3,x=0

Find the zeros of (x-5)^2+7(x-5)+10=0

The zeros of (x-5)^2+7(x-5)+10=0 are x=3,x=0

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(x - 5)^{2} + 7 (x - 5) + 10 = 0

x = 3, x = 0

Solution steps

(x - 5)^{2} + 7 (x - 5) + 10 = 0

Expand

(x - 5)^{2} + 7 (x - 5) + 10 : x^{2} - 3 x

x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

x = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

x = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 3, x = 0

4 x^{2} - 24 x + 32 = 0

16 x^{2} - 8 x = 0

3 y^{2} + 12 y + 12 = 0

18 x^{2} - 12 x = 0

x + x^{2} = 2

What are the solutions to the equation (x-5)^2+7(x-5)+10=0 ?
The solutions to the equation (x-5)^2+7(x-5)+10=0 are x=3,x=0
Find the zeros of (x-5)^2+7(x-5)+10=0
The zeros of (x-5)^2+7(x-5)+10=0 are x=3,x=0