What are the solutions to the equation x+x^2=2 ?

The solutions to the equation x+x^2=2 are x=1,x=-2

Find the zeros of x+x^2=2

The zeros of x+x^2=2 are x=1,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x + x^{2} = 2

x = 1, x = - 2

Solution steps

x + x^{2} = 2

Move

2

to the left side

x + x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

x_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 3}{2 \cdot 1}, x_{2} = \frac{- 1 - 3}{2 \cdot 1}

x = \frac{- 1 + 3}{2 \cdot 1} : 1

x = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 1, x = - 2

2 (x - 1)^{2} = 98

6 + b^{2} = 70

2 1^{2} + 2 8^{2} = x^{2}

9 x^{2} + 6 x - 3 = 0

24 x^{2} + 48 x = 0

What are the solutions to the equation x+x^2=2 ?
The solutions to the equation x+x^2=2 are x=1,x=-2
Find the zeros of x+x^2=2
The zeros of x+x^2=2 are x=1,x=-2