What are the solutions to the equation abx^2-(b-2a)x-2=0 ?

The solutions to the equation abx^2-(b-2a)x-2=0 are x= 1/a ,x=-2/b ;\quad ab\ne 0

Find the zeros of abx^2-(b-2a)x-2=0

The zeros of abx^2-(b-2a)x-2=0 are x= 1/a ,x=-2/b ;\quad ab\ne 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ab x^{2} - (b - 2 a) x - 2 = 0

x = \frac{1}{a}, x = - \frac{2}{b}; ab \neq = 0

Solution steps

ab x^{2} - (b - 2 a) x - 2 = 0

Expand

ab x^{2} - (b - 2 a) x - 2 : ab x^{2} - b x + 2 a x - 2

ab x^{2} - b x + 2 a x - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

ab x^{2} + (- b + 2 a) x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - b + 2 a ) \pm ( - b + 2 a ) ^{2} - 4 ab ( - 2 )}{2 ab}

Simplify

(- b + 2 a)^{2} - 4 ab (- 2) : 2 a + b

x_{1, 2} = \frac{- ( - b + 2 a ) \pm ( 2 a + b )}{2 ab}; ab \neq = 0

Separate the solutions

x_{1} = \frac{- ( - b + 2 a ) + 2 a + b}{2 ab}, x_{2} = \frac{- ( - b + 2 a ) - ( 2 a + b )}{2 ab}

x = \frac{- ( - b + 2 a ) + 2 a + b}{2 ab} : \frac{1}{a}

x = \frac{- ( - b + 2 a ) - ( 2 a + b )}{2 ab} : - \frac{2}{b}

The solutions to the quadratic equation are:

x = \frac{1}{a}, x = - \frac{2}{b}; ab \neq = 0

x^{2} - 3 = 0

x, 36 x^{2} + 64 y^{2} + 360 x - 512 y + 1924 = 0

x^{2} + 8 x + 9 = - 9

x^{2} + 50 x + 336 = 0

(x - 3)^{2} = x - 1

What are the solutions to the equation abx^2-(b-2a)x-2=0 ?
The solutions to the equation abx^2-(b-2a)x-2=0 are x= 1/a ,x=-2/b ;\quad ab\ne 0
Find the zeros of abx^2-(b-2a)x-2=0
The zeros of abx^2-(b-2a)x-2=0 are x= 1/a ,x=-2/b ;\quad ab\ne 0